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When F(2) react with H(2)S a product (x)...

When `F_(2)` react with `H_(2)S` a product (x) of sulphur is formed the difference in the oxidation state of sulphur in `H_(2)S` and the in the product (x) is

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The correct Answer is:
8
`H_(2)S^(-2)+F_(2) to 2HF+S` (Sulphur)
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