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Number of moles of K(2)Cr(2)O(7) reduced...

Number of moles of `K_(2)Cr_(2)O_(7)` reduced by one mole of `Sn^(2+)` ions is

A

`1/3`

B

`3`

C

`1/6`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
A
`Cr_(2)O_7^(-2) + 3Sn^(+2) rarr 3Sn^(+4) + 2Cr^(+3)`
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