Home
Class 12
CHEMISTRY
A solution containing 25. 6 gm of sulphu...

A solution containing 25. 6 gm of sulphur dissolved in 1000 gm of napthalene gave a freezing point lowering of 0.680, then molecular formula of sulphare is
`(K_(f)` for naphthalene=6.8K kg `mol^(-1)`)

A

`s_(2)`

B

`s_(4)`

C

`S_(6)`

D

`S_(8)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

When 36g of a non-volatile, non-electrolytic solute having the empirical formula CH_(2)O is dissolved in 1.2 kg of water, the solution freezes at -0.93^(@)C . The molecular formula of the solute is ( K_(f) of water = 1.86 K kg mol^(-1) )

The solution containing 6.8g of non-ionic solute in 100g of water was found to freeze at - 0.93^@C . If K_f for water is 1.86, the molar Mass of solute is

31 g of ethylene glycol (C_2H_6O_2) is dissolved in 600g of water. The freezing point depression of the solution is (K_f for water is 1.86 K Kg mol^-1)

At 300K, 10 gm of a solute dissolved in 100gm of benzene showed a lowering of 8.8 mm in benzene. Calculate the mass of solute [Vapour pressure of pure Benzene is 121.8 mm at 300K]

A solution of sucrose (molar mass 342 "gmol"^(-1) ) has been produced by dissolving 68.5g sucrose in 1000g water. The freezing point of the solution obtained will be ( K_f for H_2O = 1.86 kg "mol"^(-1) )

0.5% aqueous KCl has freezing point -0.24^@C . Calcualte the degree of dissociation, If K_f for water is 1.86 K kg mol^(-1) .

The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53" K kg mol"^(-1) .