Home
Class 12
CHEMISTRY
Consider equimolal aqueous solutions of ...

Consider equimolal aqueous solutions of `NaHSO_(4)` and Nacl with `Delta T_(b)` and `DeltaT_(b)^(1)` as their respective boiling point elevations. The value of `underset (xrarrinfty)(Lt) (DeltaT_(b))/(DeltaT_(b))` will be

A

1

B

1.5

C

3.5

D

`2//3`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The Boiling point of the solution is (K_(b) of H_(2)O=0.52K kg mol^(-1))

underset(x to 0)"Lt" ((a^(x)+b^(x))/(2))^(1//x)=

Two intervals of time are measured as Delta t_(1) = (2.00 pm 0.02) s and Delta t_(2) (4.00pm 0.02)s . The value of sqrt( ( Deltat_(1)) ( Deltat_(2))) with correct significant figures and error is

An aqueous solution freezes at - 0.372^@C . If K_f and K_b for water are 1.86K kg "mol"^(-1) and 0.53 K kg "mol"^(-1) respectively, the elevation in boiling point of same solution in K is:

Boiling point of water 750 mm Hg is 99.63^(@)C . How much sucrose is to be added to 500 g of water such that it boils at 100^(@)C . [K_(b) for water is 0.52" K kg mol"^(-1)] i) Since boiling point is changing, apply the formula for elevation in boiling point, Delta"T"_(b)=K_(b)m ii) m=(W_(B))/(M_(B).W_(A)) So, DeltaT_(b)=(K_(b).W_(B))/(M_(B)xxW_(A)) Or W_(B)=(DeltaT_(b)xxM_(B)xxW_(A))/(K_(b)) iii) Find DeltaT_(b)" as "DeltaT_(b)=T_(b)=T_(b)-T_(b)^(0) T_(b) = Boiling point of solution T_(b)^(0) = Boiling point of pure solvent