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The Henry's constant for solubility of N...

The Henry's constant for solubility of `N_(2)` gas in water at 298K is `1.0xx10^(5)` atm. The mole fraction of `N_(2)` in air is 0.8 . The number of moles of `N_(2)` from air dissolved in 10 moles of water at 298K and 5 atm pressure is :

A

`4xx10^(-4)`

B

`4.0xx10^(-5)`

C

`5.0xx10^(-4)`

D

`4.0xx10^(-6)`

Text Solution

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The correct Answer is:
A
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