`(1)/(2)A=(1)/(3)B,` then `A:B=`

If A:B=(1)/(2):(1)/(3),B:C=(1)/(5):(1)/(3) t, then (A+B):(B+C) is equal to :

If (x+1)/(x-1)=(a)/(b) and (1-y)/(1+y)=(b)/(a), then the value of (x-y)/(1+xy) is (2ab)/(a^(2)-b^(2)) (b) (a^(2)-b^(2))/(2ab) (c) (a^(2)+b^(2))/(2ab) (d) (a^(2)-b^(2)backslash)/(ab)

If (a^(3//2)-ab^(1//2)+a^(1//2)b-b^(3//2)) is divided by (a^(1//2)-b^(1//2)) , then the quotient is :

Verify (AB)^(-1)=B^(-1)A^(-1) with A=[{:(0,-3),(1,4)],B=[(-2,-3),(0,-1):}]

If A:B=1/2:1/3, B:C=1/5:1/3 then (A+B):(B+C)=