The value of u so that the ball reaches at point A (g = 10m/s2)

A ball is dropped onto a step at a point P and rebounds with velocity u_@ at an angle of 45^@ with the vertical. The value of u_0 knowing that just before the ball hits the point Q its velocity forms an angle 30^@ with the vertical is: (g=10m//s^2)

A ball is dropped onto a step at a point P and rebounds with velocity u_@ at an angle of 45^@ with the vertical. The value of u_0 knowing that just before the ball hits the point Q its velocity forms an angle 30^@ with the vertical is: (g=10m//s^2)

A ball is thrown from the top of a 60m high tower with velocity 20sqrt(2)m//s at 45^(@) elevation.Find the radius of curvature of path at highest point. ( g=10m//s^(2) )

A small ball is rolled with speed u from point A along a smooth circular track as shown in Fig. 3E.33. If x = 3R , determine the required speed u so that the ball returns to A, the point of projection. What is the minimum value of x for which the ball can reach the point of projection ?

When a cricket ball is thrown vertically upwards, it reaches a maximum height of 5 metres. (a) What was the initial speed of the ball ? (b) How much time is taken by the ball to reach the highest point ? (g=10 m s^(-2))

A boy throws a ball upward with velocity v_(0)=20m//s . The wind imparts a horizontal acceleration of 4m//s^(2) to the left. The angle theta at which the ball must be thrown so that the ball returns to the boy's hand is : (g=10ms^(-2))

A boy throws a ball upward with velocity v_(0)=20m//s . The wind imparts a horizontal acceleration of 4m//s^(2) to the left. The angle theta at which the ball must be thrown so that the ball returns to the boy's hand is : (g=10ms^(-2))

A boy throws a ball upward with velocity v_(0)=20m//s . The wind imparts a horizontal acceleration of 4m//s^(2) to the left. The angle theta at which the ball must be thrown so that the ball returns to the boy's hand is : (g=10ms^(-2))

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :