In a typical projectile motion, tangential acceleration at the topmost point P of the trajectory is

Assertion A particle is projected with speed u at an angle theta with the horizontal. At any time during motion, speed of particle is v at angle alpha with the vertical, then v sin alpha is always constant throughout the motion. Reason In case of projectile motion, magnitude of radical acceleration at topmost point is maximum.

Assertion A particle is projected with speed u at an angle theta with the horizontal. At any time during motion, speed of particle is v at angle alpha with the vertical, then v sin alpha is always constant throughout the motion. Reason In case of projectile motion, magnitude of radical acceleration at topmost point is maximum.

At the top of the trajectory of projectile the

At the top of the trajectory of projectile the

If a stone projected from ground, takes 4 s to reach the topmost point, of its trajectory, then time of fight is

What is the acceleration of a projectile at the top of its trajectory ?

Acceleration of a particle under projectile motion at the highest point of its trajectory is :

Acceleration of a particle under projectile motion at the highest point of its trajectory is :

What is the angle between directions of velocity and acceleration at the highest point of trajectory of projectile?