Value of f(0) so that f(x) = `(log(1+bx)-log(1-ax))/x` is continuous at x = 0 is

The value of f(0) so that f(x)=(log(1+x//a)-log(1-x//b))/(x) is continuous at x=0 is

f(x) = ( log (1 +ax ) - log (1 - bx))/(x) is continuous at x = 0 then f(0) =

Find the value of f(0) so that f(x) = (log (1 + (x)/(a))- log (1 - (x)/(b)))/(x) is continuous x = 0

If the function f(x)=(log(1+ax)-log(1-bx))/(x) is continuous at x=0, then f(0)=

If the f(x) =(log(1+ax)-log(1-bx))/x , xne0 is continuous at x = 0 then, f(0) = .....

Find f(0) if the function defined as f(x) = {:{(log(1+x/a)-log(1-x/b))/x (for x ne 0) , is continuous at x = 0. ab ne 0

For the function f(x) = (log_(e )(1+x)-log_(e )(1-x))/(x) to be continuous at x = 0, the value of f(0) should be

For the function f(x) = (log_(e )(1+x)-log_(e )(1-x))/(x) to be continuous at x = 0, the value of f(0) should be

The value of f(0) for which the function : (log_(e) (1-ax) - log_(3) (1-bx))/(x) is continuous at x = 0 is :

If f(x) f(x) = (log{(1+x)^(1+x)}-x)/(x^(2)), x != 0 , is continuous at x = 0 , then : f(0) =