5 years hence, the age of a man shall be 3 times the age of his son while 5 years earlier the age of the man was 7 times the age of his son. The present age of the man is

The present age of a man is seven times the present age of his son. Two years ago, the age of the man was elevent times the age of the son. Find the present age of the man (in years)

A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son. Find their present ages.

10 years ago, the age of a father was four times the age of his son then. 10 years hence, the age of the father will be twice the age of his son. Find their present ages.

The age of a man is twice the square of the age of his son.Eight years hence,the age of the man will be 4years more than three times of the age of his son.Find their present ages.

Solve it graphically : The age of Sanjay is 4 times the age of his son. 5 years hence the age of Sanjay will be three times the age of his son. Find their present ages.

Four years ago, age of a person was 4 times that of his son. Six years later, the age of the person will be 10 years less than thrice the age of his son. Find the present ages of the person and his son

The age of a man is twice the square of the age of his son.Eight years hence,the age of the man will be 4 years more than three xx the age of his son.Find their present ages.