Let `g(x)=int_0^x f(t) dt` where fis the function whose graph is shown .

Let f and g are the functions whose graphs are shown

Let f(x)=int_(0)^(1)|x-t|dt, then

Let f ( x) = int _ 0 ^ x g (t) dt , where g is a non - zero even function . If f(x + 5 ) = g (x) , then int _ 0 ^ x f (t ) dt equals :

Let f ( x) = int _ 0 ^ x g (t) dt , where g is a non - zero even function . If f(x + 5 ) = g (x) , then int _ 0 ^ x f (t ) dt equals :

Let g(x)=int_0^x f(t).dt ,where f is such that 1/2<=f(t)<=1 for t in [0,1] and 0<=f(t)<=1/2 for t in [1,2] .Then g(2) satisfies the inequality

Let g(x)=int_0^x f(t).dt ,where f is such that 1/2<=f(t)<=1 for t in [0,1] and 0<=f(t)<=1/2 for t in [1,2] .Then g(2) satisfies the inequality

Let g(x)=int_0^x f(t).dt ,where f is such that 1/2<=f(t)<=1 for t in [0,1] and 0<=f(t)<=1/2 for t in [1,2] .Then g(2) satisfies the inequality

Let g(x)=int_0^x f(t).dt ,where f is such that 1/2<=f(t)<=1 for t in [0,1] and 0<=f(t)<=1/2 for t in [1,2] .Then g(2) satisfies the inequality

Let g(x) = int_0^(x) f(t) dt , where 1/2 le f(t) < 1, t in [0,1] and 0 < f(t) le 1/2 "for" t in[1,2] . Then :