Base of a triangle is 9 and height is 5. Base of another is 10 and height is 6 . Find the ratio of areas of these triangles.

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Base of a triangle is 9 and height is 5 . Base of another triangle is 10 and height is 6 . Find the ratio of areas of these triangles.

Base of a triangle is 9 cm and height is 5 cm. Base of another triangle is 10 cm and height is 6 cm. Find the ratio of areas of these triangles.

The base of a triangle is 14 cm and its height is 8 cm. The area of the triangle is

The base of a triangle is 12 cm and height it 8 cm. Its area is :

The base of a triangle is 12cm and height is 8cm then area of triangle is

Show that : (i) a diagonal divides a parallelogram into two triangles of equal area. (ii) the ratio of the areas of two triangles of the same height is equal to the ratio of their bases. (iii) the ratio of the areas of two triangles on the same base is equal to the ratio of their heights.

The ratio of the base and height of a triangle is 7 : 6, the sum of its base and height be 39 cm, then find the area of the triangle.