` 2.5 F` of electricity is passed through a `CuSO_4` solution. The number of gm equivalent of `Cu deposited on anode is .

2.5 faradays of electricity is passed through solution of CuSO_(4) . The number of gram equivalents of copper depsoited on the cathode would be

2.5 faradays of electricity is passed through solution of CuSO_(4) . The number of gram equivalents of c opper depsoited on the cathode would be

When 1 Faraday of electricity is passed through CuSO_4 solution, number of atoms formed is :

When 1300 coulomb of electricity passed through CuSO_(4) solution the amount of Cu deposited is

2.5 Faraday of electricity are passed through a solution of a solution of CuSO_4 . The Number of gram equivalents of copper deposited on the cathode are :

If same quantity of electricity is passed through CuCI and CuSO_(4) the ratio of the weights of Cu deposited from CuSO_(4) and CuCI is:-