`cos theta-cos7 theta=sin4 theta`

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

Prove the following : sin theta+ sin 3 theta+ sin 5 theta+sin 7 theta=4 cos theta cos2 theta sin4 theta .

If theta=7.5^(@) Find the value of quad sin8 theta*cos theta-sin6 theta cos3 thetacos2 theta*cos theta-sin3 theta*sin4 theta

(cos6 theta-cos4 theta)/(sin6 theta+sin4 theta)=-tan theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

Prove the following: "sin" theta+"sin" 3theta+"sin" 5theta+"sin" 7theta=4 cos theta cos 2theta sin 4theta .

If 3sin theta =2 cos theta , then (4sin theta - cos theta)/(4cos theta+sin theta) is equal to :

Simplify: cos theta[[cos theta , sin theta],[-sin theta , cos theta]]+sin theta[[sin theta, -cos theta],[cos theta ,sin theta]] .

Simplify: cos theta[cos theta sin theta-sin theta cos theta]+sin theta[sin theta-cos theta cos theta sin theta]

Simplify cos theta[(cos theta,sin theta),(-sin theta,cos theta)]+sin theta[(sin theta,-cos theta),(cos theta,sin theta)]