A simple hormonic motion of acceleration a and displacement x is represented by `a+4pi^(2)x=0`. What is the time period of S.H.M ?

A simple harmonic motion of acceleration 'a' and displacement 'x' is represented by a+4pi^(2)x = 0 What is the time period of S.H.M ?

A simple harmonic motion is described by a = -16x where a is acceleration and x is the displacement in meter. What is the time period?

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2))+αx=0 , its time period is.

A simple pendulum is described by a = -16x , where a is acceleration, x is displacement in meter. What is the time period ?

The equation of motion of a particle executing S.H.M. is a = - bx , where a is the acceleration of the particle, x is the displacement from the mean position and b is a constant. What is the time period of the particle ?

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :