Dividing `f(z)` by `z- i`, we obtain the remainder i and dividing it by `z + i`, we get the remainder 1 + i, then remainder upon the division of `f(z)` by `z^2+1` is

Dividing f(z) by z-i, we obtain the remainder 1-i and dividing it by z+i, we get the remainder 1+i. Then, the remainder upon the division of f(z) by z^(2)+1 , is

Dividing f(z) by z-i, we obtain the remainder 1-i and dividing it by z+i, we get the remainder 1+i. Then, the remainder upon the division of f(z) by z^(2)+1 , is

Dividing f(z) by z-i, we obtain the remainder 1-i and dividing it by z+i, we get the remainder 1+i. Then, the remainder upon the division of f(z) by z^(2)+1 , is

54Z leaves remainder 2 when divided by 5 and leaves remainder 1 when divided by 3, what is the value of Z?

When a natural number x is divided by 5, the remainder is 2. When a natural number y is divided by 5, the remainder is 4, The remainder is z when x+y is divided by 5. The value of (2z-5)/(3) is

Find the remainder when the polynomital p(z)=z^(3)-3z+2 is divided by z-2.

On dividing a number by 13, we get 1 as remainder. If the quotient is divided by 5. we get 3 as a remainder. If this number is divided by 65, what will be the remainder ?

If the remainders respectively when f(z) = z^(3)+z^(2)+2z+1 is divided with z-i and z+i are 1+3i and 1+i then find the remainder when f(z) is divided with z^(2)+1 ?

x=20, y=32 and z=12 {:("Quantity A","Quantity B"),("The remainder when x is","The remainder when y is "),("divided by z","divided by z"):}