Let S be a sphere with radius r. If we approximate the change of volume of S by `h.A| _(r_0) +(h^2)/2(dA)/(dr)|_(r=r_0)` where A is surface area, when radius is changed from `r_0` to `(r_0 + h),` then the absolute value of error in our approximation is

Let S be a square with sides of length x. If we approximate the change in size of the area of S by h (dA)/(dx)|_(x=x_0) , when the sides are changed from x_0 to x_0 + h , then the absolute value of the error in our approximation, is

Let S be a square with sides of length x. If we approximate the change in size of the area of S by h (dA)/(dx)|_(x=x_0) , when the sides are changed from x_0 to x_0 + h , then the absolute value of the error in our approximation, is

Let S be a square with sides of length x.If we approximate the change in size of the area of S by h(dA)/(dx)|_(x=x_(0)), when the sides are changed from x_(0) to x_(0)+h, then the absolute value of the error in our approximation,is

If the surface area of a sphere of radius r is increasing uniformly at the rate cm^(2)//s , then the rate of change of its volume is :

The rate of change of the volume of the sphere w.r.t its surface area, when its radius is 2cm is

The volume of a sphere is given by V= 4/3 pi R^3 where R is the radius of the sphere (a). Find the rate of change of volume with respect to R. (b). Find the change in volume of the sphere as the radius is increased from 20.0 cm to 20.1 cm. Assume that the rate does not appreciably change between R=20.0 cm to R=20.1 cm.

The volume of a sphere is given by V= 4/3 pi R^3 where R is the radius of the sphere (a). Find the rate of change of volume with respect to R. (b). Find the change in volume of the sphere as the radius is increased from 20.0 cm to 20.1 cm. Assume that the rate does not appreciably change between R=20.0 cm to R=20.1 cm.

The volume of a sphere is given by V=4/3 piR^(3) where R is the radius of the radius of the sphere. Find the change in volume of the sphere as the radius is increased from 10.0 cm to 10.1 cm . Assume that the rate does not appreciably change between R=10.0 cm to R=10.1 cm

The volume of a sphere is given by V=4/3 piR^(3) where R is the radius of the radius of the sphere. Find the change in volume of the sphere as the radius is increased from 10.0 cm to 10.1 cm . Assume that the rate does not appreciably change between R=10.0 cm to R=10.1 cm

If V denotes the volume and S is the surface area of a sphere. If radius of sphere is 2 cm, then the rate of change of V w.r.t. S is