In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is `5460 Å`. Then, angular position of first dark fringe is approximately

In Young's double slit experiment, the distance between two sources is 0.1mm . The distance of screen from the sources is 20cm . Wavelength of light used is 5460Å . Then angular position of the first dark fringe is

In young's double slit experiment the distance between two sources is 0.1//pimm .the distance of the screen from the source is 25cm .wavelength of light used is 5000Å .Then the angular position of the first dark fringe is-

In Young's double slit experiment, the distnace between two sources is 0.1//pimm . The distance of the screen from the source is 25 cm. Wavelength of light used is 5000Å Then what is the angular position of the first dark fringe.?

In Young's double slit experiment, the distnace between two sources is 0.1//pimm . The distance of the screen from the source is 25 cm. Wavelength of light used is 5000Å Then what is the angular position of the first dark fringe.?

In Young's double slit experiment, the distnace between two sources is 0.1//pimm . The distance of the screen from the source is 25 cm. Wavelength of light used is 5000Å Then what is the angular position of the first dark fringe.?

In Young.s double slit experiment the distance between the sources is 7.7 mu""m . If the wavelength of light used is 500 nanometre, the angular position of the third dark ringe from the centre fringe is

In Young's double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m . If the fringe width on the screen is 0.06 cm , then lambda =