Light of wavelength `4000Å` is allowed to fall on a metal surface having work function 2 eV. The maximum velocity of the emitted electrons is
`(h=6.6xx10^(-34)Js)`

Light of wavelength 3000Å is incident on a metal surface whose work function is 1 eV. The maximum velocity of emitted photoelectron will be

Light of wavelength 3000Å is incident on a metal surface whose work function is 1 eV. The maximum velocity of emitted photoelectron will be

Light of wavelength 3000 Å falls on a metal surface having work function 2.3 eV. Calculate the maximum velocity of ejected electrons. (Planck's constant , h = 6.63 xx 10 ^( - 34 ) J.s. , velocity of light c = 3 xx10 ^( 8 ) m//s , mass of an electron = 9.1 xx 10 ^( -31 ) kg )

Light of wavelength 500 nm is incident on a metal with work functin 2.28 eV.The de-Broglie wavelength of the emitted electron is :[ h=6.6xx10^(-34Js) and c=3xx10^(8)m//s ]

The light radiation of wavelength 6000 Å falls on a metal . The threshold frequency of a metal surface is 4 xx 10^(14) Hz . The maximum velocity of the emitted photoelectrons is

A light of wavelength 5000 Å falls on a photosensitive plate with photoelectric work function 1.90 eV. Kinetic energy of the emitted photoelectrons will be (h = 6.63 xx 10^(-34)J.s)

For photoelectric emission, threshold wavelength of a metal is 2460 Å . If ultraviolet light of wavelength 1810 Å be incident on the metal, what will be the maximum kinetic energy of the emitted electrons? [Planck's constant = 6.62xx10^(-34) J.s , velocity of light in veccuum = 3xx10^(8) m.s^(-1) ]

If Photon having wavelength 6.2nm was allowed to strike a metal plate having work function 50eV then calculate wavelength associated with emitted electron :