A string fixed at both ends vibrates in a resonant mode with a separation of 2.0cm between the consecutive nodes. For the next higher resonants frequecy this separation to 1.6cm. The length of the string is

A uniform string fixed at both ends vibrates in a resonant mode with a separation of 2.0 cm between the consecutive nodes. For next higher resonant frequency, this separation is reduced to 1.6 cm. The length of the string is

A uniform string fixed at both ends vibrates in a resonant mode with a separation of 2.0 cm between the consecutive nodes. For next higher resonant frequency, this separation is reduced to 1.6 cm. The length of the string is

A string, fixed at both ends, vibrates in a resonant mode with a separation of 2.0 cm between the consecutive nodes. For the next higher resonant frequency, this separation is reduced to 1.6 cm. Find the length of the string.

A string, fixed at both ends, vibrates in a resonant mode with a separation of 2.0 cm between the consecutive nodes. For the next higher resonant frequency, this separation is reduced to 1.6 cm. Find the length of the string.

A string, fixed at both ends, vibrates in a resonant mode with a separation of 2.0 cm between the consecutive nodes. For the next higher resonant frequency, this separation is reduced to 1.6 cm. Find the length of the string.

A taut string fixed at both ends vibrates in n^(th) overtone. The separation between adjacent node and antinode is equal to 'd'. Then string length is

If a string fixed at both ends vibrates in four loops. The wavelength is 10 cm. The length of string is

If a string fixed at both ends, vibrates in its fourth harmonic, the wavelength is 15 cm. What is the length of the string ?

A string fixed at both the ends forms standing waves with node separation of 5 cm. If the velocity of waves travelling in the string is 4 m/s, then the frequency of vibration of the string will be