Home
Class 12
CHEMISTRY
Solid Na(2)SO(4) is slowly added to a so...

Solid `Na_(2)SO_(4)` is slowly added to a solution which is 0.020 M in `Ba(NO_(3))_(2)` and 0.020 M is `Pb(NO_(3))_(2)`. Assume that there is no increase in volume on adding `Na_(2)SO_(4)`. There preferential precipitation takes place. What is the concentration of `Ba^(2+)` when `PbSO_(4)` starts to precipitate? `[K_(sp)(BaSO_(4))=1.0xx10^(-10) and K_(sp)(PbSO_(4))=1.6xx10^(-8)]`

Promotional Banner

Similar Questions

Explore conceptually related problems

A solution is 0.10 M Ba(NO_(3))_(2) and 0.10 M Sr(NO_(3))_(2.) If solid Na_(2)CrO_(4) is added to the solution, what is [Ba^(2+)] when SrCrO_(4) begins to precipitate? [K_(sp)(BaCrO_(4))=1.2xx10^(-10),K_(sp)(SrCrO_(4))=3.5xx10^(-5)]

A solution is 0.10 M Ba(NO_(3))_(2) and 0.10 M Sr(NO_(3))_(2.) If solid Na_(2)CrO_(4) is added to the solution, what is [Ba^(2+)] when SrCrO_(4) begins to precipitate? [K_(sp)(BaCrO_(4))=1.2xx10^(-10),K_(sp)(SrCrO_(4))=3.5xx10^(-5)]

A solution is 0.10 M Ba(NO_(3))_(2) and 0.10 M Sr(NO_(3))_(2.) If solid Na_(2)CrO_(4) is added to the solution, what is [Ba^(2+)] when SrCrO_(4) begins to precipitate? [K_(sp)(BaCrO_(4))=1.2xx10^(-10),K_(sp)(SrCrO_(4))=3.5xx10^(-5)]

What is the concentration of Pb^(2+) when PbSO_(4) (K_(sp)=1.8xx10^(-8)) begins to precipitate from a solution that is 0.0045 M in SO_(4)^(2-) ?

What is the concentration of Pb^(2+) when PbSO_(4) (K_(sp)=1.8xx10^(-8)) begins to precipitate from a solution that is 0.0045 M in SO_(4)^(2-) ?

What is the concentration of Pb^(2+) when PbSO_(4) (K_(sp)=1.8xx10^(-8)) begins to precipitate from a solution that is 0.0045 M in SO_(4)^(2-) ?

In an aqueous solution 10^(-2) M Na_(2)SO_(4) and 10^(-2) M NaI are present. Now pure Pb(NO_(3))_(2) is added gradually then calculate concentration of SO_(4)^(2-) when PbI_(2) start precipitating in solution [ K_(sp) (PbI_(2))=10^(-9) and K_(sp)(PbSO_(4))=10^(-8) ].

What is minimum concentration of SO_(4)^(2-) required to precipitate BaSO_(4) in solution containing 1 xx 10^(-4) mole of Ba^(2+) ? ( K_(sp) of BaSO_(4) = 4 xx 10^(-10) )