The molar mass of a solute X in g `mol^(-1)`, if its 1% solution is isotonic with a 5% solution of cane sugar (molar mass = `342 g mol^(-)`), is

At what concentration of solute 'P' the solution will be isotonic with a 5 percent solution of urea? (Molar mas of 'P'=342g mol^(-1) )

A solution of 17.1 w% of sucrose ( molar mass = 342 " g mol"^(-1) ) is isotonic with a x w% solution of oxalic acid ( molar mass = 90g " mol"^(-1) ). Assume the degree of dissociation of oxalic acid as 0.01. What is x ?

A solution contains 15 g urea (molar mass=60 g-mol^-1) per litre of solution in water has the same osmotic pressure as a solution of glucose (molar mass=180 g mol^-1) in water. Calculate the mass of glucose present in one litre of its solution.

A 5% by mass of an aqueous solution of A of molar mass 342"gmol"^(-1) is isotonic with 0.878% by mass of an aqueous solution of another substance B. The molar mass of B in "gmol"^(-1) is

A solution containing 15g urea (molar mass = 60g/mol) per litre of solution in water is isotonic with the solution of glucose (molar masss 180g//mol ) in water calculate the mass of glucose present in one litre of its solution,.

The osmotic pressure of 5% aqueous solution of sugar (mol. Mass 342) at 15^@C is