A wire of `15 Omega` resistance is gradually stretched to double its length . IT is then cut into two equal parts. These parts are then connected in parallel across a 3.0 volt battery .Find the current drawn from the battery.

A wire of 20 Omega resistance is gradually stretched to double its original length. It is then cut into two equal parts. These parts are then connected in parallel across a 4.0 volt battery. Find the current drawn from the battery.

A wire of 20 Omega resistance is gradually stretched to double its original length. It is then cut into two equal parts. These parts are then connected in parallel across a 4.0 volt battery. Find the current drawn from the battery.

A wire of 15 Omega resistance is gradually stretched to double in original length. it is then cut into two equal parts .These parts are then connected in parallel across a 3.0 volt battery. Find the current draw from the battery .

A wire of 15 Omega resistance is gradually stretched to double in original length. it is then cut into two equal parts .These parts are then connected in parallel across a 3.0 volt battery. Find the current draw from the battery .

A wire of resistance r is cut into m equal parts. These parts are then connected in parallel . The equivalent resistance of the combination will be