If the area enclosed by the curve `y^(2)=4x` and `16y^(2)=5(x-1)^(3)` can be expressed in the form `(L sqrt(M))/(N)` where L and N are relatively prime and M is a prime, find the value of `(L+M+N)`.

If x and y vary inversely, find the values of l, m and n :

If x and y vary inversely, find the values of l, m and n :

L_(1):x+y=0 and L_(2)*x-y=0 are tangent to a parabola whose focus is S(1,2). If the length of latus-rectum of the parabola can be expressed as (m)/(sqrt(n)) (where m and n are coprime then find the value of (m+n)

S={(x,y)|x,y in R,x^(2)+y^(2)-10x+16=0} The largest value of (y)/(x) can be put in the form of (m)/(n) where m,n are relatively prime natural numbers,then m^(2)+n^(2)=

Let S={(x,y)|x,y in R, x^2+y^2-10x+16=0} . The largest value of y/x can be put in the form of m/n where m, n are relatively prime natural numbers, then m^2+n^2=

lim_(x rarr2)[(x-2)/(x^(2)-4)-(1)/(x^(3)-3x^(2)+x)]=(1)/(m) where l and m are mutually prime then the value of (l+m)

If l= log "" ( 5)/(7) , m = log ""( 7)/(9) and n = 2 ( log 3 - log sqrt5) , find the value of l+ m + n

If x,yinR^+ and log_10(2x)+log_10y=2 , log_10x^2-log_10(2y)=4 and x+y=m/n ,Where m and n are relative prime , the value of m-3n^(6) is

If x,yinR^+ and log_10(2x)+log_10y=2 , log_10x^2-log_10(2y)=4 and x+y=m/n ,Where m and n are relative prime , the value of m-3n^(6) is