Two functions f & g have first & second derivatives at x=0 & satisfy the relations, `f(0) = 2/(g(0)), f'(0)=2g'(0) = 4g(0), g"(0)= 5 f"(0)=6f(0) = 3` then-

f(x)=e^x.g(x) , g(0)=2 and g'(0)=1 then f'(0)=

If f(x)=(e^(x))/(g(x)),g(0)=6,g'(0)=2 , then f'(0) is

If f(x)=e^(x)g(x),g(0)=2,g'(0)=1, then f'(0) is

If f(x)=e^(x)g(x),g(0)=2,g'(0)=1, then f'(0) is

Let f(x) = e^(x)g(x) , g(0)=2 and g (0)=1 , then find f'(0) .

Let f(x)>0 and g(x)>0 with f(x)>g(x)AA x in R are differentiable functions satisfying the conditions (i) f(0)=2,g(0)=1 , (ii) f'(x)=g(x) , (iii) g'(x)=f(x) then

Let f, g and h are differentiable functions. If f(0) = 1; g(0) = 2; h(0) = 3 and the derivatives of theirpair wise products at x=0 are (fg)'(0)=6;(g h)' (0) = 4 and (h f)' (0)=5 then compute the value of (fgh)'(0) .