Home
Class 12
CHEMISTRY
A galvanic cell consists of a metallic z...

A galvanic cell consists of a metallic zinc plate immersed in 0.1 M `Zn (NO_(3))_(2)` solution and metallic plate of lead in 0.02M `Pb(NO_(3))_(2)` solution. Calculate the emf of the cell.
Write the chemical equation for the electrode reactions and represent the cell.
`("Given" : E^(@) Zn^(2+)ZN=0.76V, " " E^(@)Pb^(2+)//Pb = -0.13V)`

Promotional Banner

Similar Questions

Explore conceptually related problems

A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn (NO_(3))_(2) solution and metallic plate of lead in 0.02M Pb(NO_(3))_(2) solution. Calculate the emf of the cell. Write the chemical equation for the electrode reactions and represent the cell. ("Given" : E^(@) Zn//Zn^(2+)=0.76V, " " E^(@)Pb^(2+)//Pb = -0.13V)

Read the passage given below and answer the question. A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn(NO_(3))_(2) solution and metallic plate of lean in 0.02 M Pb (NO_(3))_(2) solution. Q. Calculate the emf of the cell.

Read the passage given below and answer the question. A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn(NO_(3))_(2) solution and metallic plate of lean in 0.02 M Pb (NO_(3))_(2) solution. Q. How will the cell be represented?

Read the passage given below and answer the question. A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn(NO_(3))_(2) solution and metallic plate of lean in 0.02 M Pb (NO_(3))_(2) solution. Q. What product is obtained at cathode ?

Read the passage given below and answer the question. A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn(NO_(3))_(2) solution and metallic plate of lean in 0.02 M Pb (NO_(3))_(2) solution. Q. Which of the following statement is not correct about an inert electrode in a cell ?

A galvanic cell is made by dipping a Zn - rod in 0.1 (M) Zn(NO_(3))_(2) and a Pb - rod in 0.25 (M) Pb(NO_(3))_(2) solution. Calculate EMF of the cell, write the cell reaction and represent the cell. Given : E_(Pb^(2+)|Pb)^(@)=-0.13V, E_(Zn^(2+)|Zn)^(@)=-0.77V.

Write the cell reaction and cell potential of the cell Zn//Zn^(2+)(0.01 M)abs"Ag^+(0.1M)//Ag. Given E^0(Zn^(2+)//Zn)=-0.76V E^0(Ag^+//Ag)=+0.80V .