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The number of ways in which 5 red b...

The number of ways in which 5 red beeds and 4 yellow beeds of different sizes can be made out to form a necklace so that no two yellow beads come together is

A

`(4!""^(5)P_(4))/(2)`

B

`6!xx""^(4)P_(5)`

C

`(6!xx""^(4)P_(5))/(2)`

D

`4!xx""^(5)P_(4)`

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A
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AAKASH SERIES-PERMUTATIONS & COMBINATIONS-PRACTICE EXERCISE
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  2. If the letters of the word 'MIRROR' are arranged as in a dictionary, t...

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  4. All the numbers that can be formed using the digits 1,2,3,4,5 a...

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  5. The sum of numbers formed by taking all the digits 2, 4, 6, 8 is

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  15. If ""^(35)C(n+7)=""^(35)C(4n-2), then all the values of n are given by

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  16. IF ""^(15)C(r+3)=""^(15)C(2r-3), then r=

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  17. ""^(n-2)C(r)+2.""^(n-2)C(r-1)+""^(n-2)C(r-2) is equal to

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