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sum( r=0 )^ ( 10) ( 40 -r)C (5)=...

`sum_( r=0 )^ ( 10) ( 40 -r)C _(5)=`

A

`""^(41)C_(5)-""^(30)C_(5)`

B

`""^(41)C_(6)-""^(30)C_(6)`

C

`""^(41)C_(5)+""^(30)C_(5)`

D

`""^(41)C_(6)`

Text Solution

Verified by Experts

The correct Answer is:
B
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