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In an experiment the following observast...

In an experiment the following observastions are recorded. L = 2.890 m, M = 3.00 kg : a = 0.087 cm , d = 0.041 cm, g = 9.8 1 `ms^(-2)`, using the formula `y=(4MgL)/(pi d^(2)a)`

A

In this experiment to calculate the maximum permissible error, we can consider, `(Delta Y)/(Y)=(Delta M)/(M)+(Delta L)/(L)+(Delta g)/(g)-2((Delta d)/(d))-((Delta a)/(a))`

B

In this experiment to calculate the maximum permissible error, we can consider, `(Delta Y)/(Y)=(Delta M)/(M)+(Delta L)/(L)-2((Delta d)/(d))-((Delta a)/(a))`

C

In this experiment to calculate the maximum permissible error, we can consider, `(Delta Y)/(Y)=(Delta M)/(M)+(Delta L)/(L)+2((Delta d)/(d))+((Delta a)/(a))`

D

The percentage error in the calculation of Y is 6.36%

Text Solution

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The correct Answer is:
C, D
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