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A particle moves in XY plane under the i...

A particle moves in XY plane under the influence of a force such that its linear momentum is `barP = A[(coskt)hati + (sin kt)(-hatj)]` , where A and k are positive constants. 

A

The magnitude of the force is Ak

B

The angle between force and momentum is  `pi/2`

C

The angle between force and momentum is it `pi`

D

The angle between acceleration and velocity vectors is always `pi//2`

Text Solution

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The correct Answer is:
A, B, D
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