Two blocks `m_(1) and m_(2)` are connected by a massless spring of force constant k `F_(1) and F_(2)` are two forces acting on m and `m_1 and m_2` as shown. The arrangement is on a horizontal plane.

Options

A. If the blocks move with same acceleration, then `a_(1) =a_(2) = (F_1-F_2)/(m_(1)+m_(2))=a_0`
B. If the blocks move with the same acceleration, then the spring force is `(F_1m_2+F_2m_1)/(m_1+m_2)`
C. If `F_2` is with drawn at an instant, when both of them have common acceleration, then `a_1 =a_0 and a_2 =a_0 +F_2/m_2`
D. If `F_2` is with drawn at an instant when `m_1 and m_2` have common acceleration then `a_1 =a_0 and a_2 =a_0 +F_2/m_2`

Answer

A, B, C