Home
Class 11
PHYSICS
A block of mass m is placed on a wedge o...

A block of mass m is placed on a wedge of mass M. Coefficient of friction between them is `mu gt cot theta.` The minimum acceleration of the wedge at which block appears stationary relative to wedge is

A

`(g (sin theta- mu cos theta))/( cos theta + mu sin theta)`

B

`(g (sin theta + mu cos theta))/(cos theta - mu sin theta)`

C

`(g(cos theta + mu sin theta ))/(sin theta - mu cos theta )`

D

`g (sin theta + mu cos theta )`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • FRICTION

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE PRACTICE SHEET (ADVANCED) (MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS)|1 Videos

  • FRICTION

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LELVL-II) (LECTURE SHEET (ADVANCED)) (LINKED COMPREHENSION TYPE QUESTIONS)|2 Videos

  • FLUID MECHANICS

    AAKASH SERIES|Exercise Questions for Descriptive Answers|14 Videos

  • GAUSS.S LAW

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|12 Videos

Similar Questions

Explore conceptually related problems

Find the minimum acceleration of the wedge so that block under free fall

A block of mass 'm' is placed on wedge of mass 'M'. If all the surfaces are smooth Normal reaction between the wedge and block is

A block of mass 'm' is placed on wedge of mass 'M'. If all the surfaces are smooth Accelaration of wedge 'A' is

Minimum acceleration of wedge such that friction on block becomes zero, is "_____"

A block of mass'm' is placed on floor of a lift which is rough. The coefficient of friction between the block and the floor is mu . When the lift falls freely, the block is pulled horizontally on the lift floor. The force of friction is

A block of mass m is in contact with the cart C as shown in the figure. The coefficient of static friciton between the block and the cart is mu . The acceleration a of the cart that will prevent the block from falling statisfies.