Home
Class 11
PHYSICS
A uniform beam of mass m is inclined at ...

A uniform beam of mass m is inclined at an angle`theta` to the horizontal. Its upper end produces a ninety degree bend in a very rough rope tied to a wall and it's lower end rests on a rough floor. If coefficient of static friction between beam & floor is ` mu _(s)` determine the maximum value of M that can be suspended from the top before the beam slips.

A

`(m ( mu_(2) sin theta))/(2(cos theta - mu_(s) sin theta))`

B

`(m( 2 mu_(s) sin theta - cos theta))/(2 (cos theta - mu_(s) sin theta))`

C

`(m)/(4) ((mu _(s) sin theta))/( (2 cos theta - mu _(s) sin theta))`

D

`(m)/(2) ((mu _(s) sin theta))/((2 cos theta - mu_(s) sin theta))`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • FRICTION

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE PRACTICE SHEET (ADVANCED) (MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS)|1 Videos

  • FRICTION

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LELVL-II) (LECTURE SHEET (ADVANCED)) (LINKED COMPREHENSION TYPE QUESTIONS)|2 Videos

  • FLUID MECHANICS

    AAKASH SERIES|Exercise Questions for Descriptive Answers|14 Videos

  • GAUSS.S LAW

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|12 Videos

Similar Questions

Explore conceptually related problems

A small body of mass 1kg is projected with initial velocity 10sqrt2 m//s on a rough horizontal surface. The coefficient of friction between the body and surface varies as mu = 5x where x is the displacement of the body. The distance travelled by the body before coming to rest__

A uniform cylinder of radius 1 m, mass 1 kg spins about its axis with an angular velocity 20 rad/s. At certain moment, the cylinder is placed into a corner as shown in the figure. The coefficient of friction between the horizontal wall and the cylinder is mu , whereas the vertical wall is frictionless. If the number of rounds made by the cylinder is 5 before it stops, then the value of mu is (acceleration due to gravity, g = 10 m//s^2 )