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A particle moves in a circular path such...

A particle moves in a circular path such that its speed v varies with distance as `V= alphasqrt(s)` where `alpha` is a positive constant. Find the acceleration of the particle after traversing a distance s.

A

`alpha^(2)sqrt((1)/(4)+ (s^(2))/(R^(2)))`

B

`alpha^(2)sqrt((R^(2))/(4s^(2))+ (s^(2))/(R^(2)))`

C

`alphasqrt((1)/(4)+ (s^(2))/(R^(2)))`

D

`alphasqrt((R^(2))/(4s^(2))+ (s^(2))/(R^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
A
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