A block of mass 'm' is kept on a horizontal ruler. The friction coefficient between the ruller and the block is 'mu'. The ruller is fixed at one end and the block is at a distance (L) from fixed end the ruler is rotated about the fixed end in the horizontal plane. If angular speed of the ruler is uniformly increased from zero at an angular acceleration `alpha` when the angular speed be `omega= (mu^(2)g^(2)-L^(2)alpha^(2))^(2//n)` the block will slip. Then n= ..........

Answer

8