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A particle of mass m is revolving in a h...

A particle of mass m is revolving in a horizontal circle on a smooth table by an in extensible massless string if the initial speed of the particle is `V_(0)` and the particle has tangential acceleration of constant magnitude a,
If the breaking strength of the string is equal to weight of the stone. The time after which the string will break

A

`(1)/(a)(sqrt(gR)-V_(0))`

B

`(V_(0))/(a)(sqrt(gR)-V_(0))`

C

`(1)/(a)(2gR-V_(0))`

D

`(V_(0))/(a)(2gR-V_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
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