Home
Class 11
PHYSICS
A particle of mass m is revolving in a h...

A particle of mass m is revolving in a horizontal circle on a smooth table by an in extensible massless string if the initial speed of the particle is `V_(0)` and the particle has tangential acceleration of constant magnitude a,
If `V_(0) =0` then the distance covered by the stone till the string ruptures

A

`(R)/(2a)`

B

`(gR)/(2a)`

C

`(g)/(2aR)`

D

`(2gR)/(a)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • HORIZONTAL CIRCULAR MOTION

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-III (Applications of Circular Motion (LEVEL-I (Straight Objective Type Questions))))|13 Videos

  • HORIZONTAL CIRCULAR MOTION

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-III (Applications of Circular Motion (LEVEL-II (Straight Objective Type Questions))))|9 Videos

  • HORIZONTAL CIRCULAR MOTION

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-II (LEVEL-II (Straight Objective Type Questions)))|5 Videos

  • GRAVITATIONAL

    AAKASH SERIES|Exercise EXERCISE -3|154 Videos

  • KINEMATICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED)) (Integer Type Questions)|12 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m is revolving in a horizontal circle on a smooth table by an in extensible massless string if the initial speed of the particle is V_(0) and the particle has tangential acceleration of constant magnitude a, If the breaking strength of the string is equal to weight of the stone. The time after which the string will break

A particle of mass m is revolving in a horizontal circle on a smooth table by an in extensible massless string if the initial speed of the particle is V_(0) and the particle has tangential acceleration of constant magnitude a, After what time the tension of the string will be equal to T (gt (mv_(0)^(2))/(R))

A particle moves along circle of radius ((20)/(pi)) m with constant tangential acceleration. If the speed of the particle is 80 m//s at the end of the second revolution after motion has begun, the tangential acceleration is

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals V_(0) then The speed of the particle as a function of the distance coverd will be

A particle moves in a circle in such a way that, its tangential deceleration is numerically equal to its radial acceleration. If the initial velocity of the particle is V_(0) , find the variation of its velocity with time

A mass of 0.1 kg is rotated in a vertical circle using a string of legth 20 cm. When the string makes an angle 30^(@) with the vertical, the speed of the mass is 1.5ms^(-1) . The tangential acceleration of the mass at that instant is