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A particle moves with deceleration along...

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals `V_(0)` then
The speed of the particle as a function of the distance coverd will be

A

`V= V_(0)e^(-s//R)`

B

`V= V_(0)e^(s//R)`

C

`V= V_(0)e^(-R//s)`

D

`V= V_(0)e^(R//s)`

Text Solution

Verified by Experts

The correct Answer is:
A
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