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A particle moves with deceleration along...

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals `V_(0)` then
The total acceleration of the particle as function of velocity and distance covered

A

`a= sqrt(2)(v^(2))/(R)`

B

`a= sqrt(2)(v)/(R)`

C

`a= sqrt(2)(R)/(v)`

D

`a= (2R)/(v)`

Text Solution

Verified by Experts

The correct Answer is:
A
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