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A particle is moving along a horizontal ...

A particle is moving along a horizontal circle with a speed `V = at - bt^(3)`. Then angular displacement of particle at any instant is (consider at `t=0 , theta_(0) = 0` and 'r' is radius of circle and `theta` is angular displacement at any instant)

A

`theta= (at^(2))/(2r)- (bt^(4))/(4r)`

B

`theta= (at^(3))/(6r)-(bt^(4))/(3r)`

C

`theta= (at)/(2r)-(bt^(2))/(3r)`

D

`theta= (at)/(r)-(bt^(3))/(r)`

Text Solution

Verified by Experts

The correct Answer is:
A
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