`(sin7theta+6sin5theta+17sin3theta+12sintheta)/(sin6theta+5sin4theta+12sin2theta)=`

(sin7 theta+6sin5 theta+17sin3 theta+12sin theta)/(sin6 theta+5sin4 theta+12sin2 theta)

(sin7 theta+6sin5 theta+17sin3 theta+12sin theta)/(sin6 theta+5sin4 theta+12sin2 theta)=

sintheta+sin7theta=sin4theta

sin2theta-sin4theta+sin6theta=0

sin2theta+sin4theta=sin6theta

sintheta+sin2theta+sin4theta+sin5theta=0

The value of expression (sin theta+3sin3 theta+5sin5 theta+3sin7 theta)/(sin2 theta+2sin4 theta+3sin6 theta) where theta=(4 pi)/(5) is equal to

Prove that (sin theta sin9theta+sin 3 thetasin5 theta)/(sinthetacos 9theta+sin3theta cos5theta)=tan 6 theta

Provethat: (cos3theta)/(sin2thetasin4theta)+(cos5theta)/(sin4thetasin6theta)+(cos7theta)/(sin6thetasin8theta) =1/(2sintheta)(cosec2theta- cosec8theta)