A square ABCD of diagonal length 2a, is folded along the diagonal AC so that the planes DAC, BAC are at right angles. The shortest distance between DC and AB is

A square PORS of side length p is folded along the diagonal PR so that planes PRQ and PRS are perpendicular to one another,the shortest distance between PQ and RS is (P)/(k sqrt(2)), then k

In a quadrilateral ABCD, with unequal sides if the diagonals AC and BD intersect at right angles, then

If the length of the diagonal AC of a square ABCD is 5.2cm, then the area of the square is :

If the length of the diagonal AC of a square ABCD is 5.2 cm, then the area of the square is :

In the figure, diagonal AC of a quadrilateral ABCD bisects the angles A and C. Prove that AB = AD and CB = CD.

In a square ABCD, the diagonal overline (AC) is drawn. Then /_BAC= ………………degrees.

Three statements are given below: I. In a rectangle ABCD, the diagonal AC bisects angle A as well as angle C. II. In a square ABCD, the diagonal AC bisects angle A as well as angle C. III. In a rhombus ABCD, the diagonal AC bisects angle A as well as angle C. Which is true?