" (ii) "cos3x+cos2x=sin(3x)/(2)+sin(x)/(2)

cos3x-cos2x=sin3x

The values of x_(1) between 0 and 2 pi, satisfying the equation cos3x+cos2x=(sin(3x))/(2)+(sin x)/(2) are

Solve : cos3x+cos2x=sin((3x)/2)+sin(x/2) , (0lexlepi)

Prove that cos8x-cos5x=-2sin((13x)/(2))sin((3x)/(2))

If cos 3x + cos 2x = sin (3x//2)+sin(x//2), 0 le x le 2pi , then x =

The values of x, between 0 and 2 pi . satisfying the equation cos 3 x + cos 2 x = sin ""(3 x)/( 2) + sin (x)/(2) are

Solve : cos 3x + cos 2x = sin ""(3)/(2) x + sin "" (1)/(2) x, 0 lt x le pi.