[" If the equation of the locus of a point equidistant from the points "(a,b_(1))" and "(a_(2),b_(2))" is "],[(a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0," then the value of 'c' is "]

If the equation of the locus of a point equi-distant from the points (a_(1), b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c is

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c is

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c'is:

If the equation of the locus of a point equidistant from the points (a_(1), b_(1)) and (a_(2), b_(2)) is : (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 , then c =

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a-1-a_(2))x+(b_(1)-b_(2))y+c=0, then the value of c is

Find the equation of locus of point equidistant from the points (a_(1)b_(1)) and (a_(2),b_(2)) .

Find the equation of locus of point equidistant from the points (a_(1)b_(1)) and (a_(2),b_(2)) .

If the equation of the locus of a point equidistant from the points ( a_ 1 , b _ 1 ) and ( a _ 2, b _ 2 ) is ( a _ 1- a _ 2 ) x + ( b _ 1 - b _ 2 ) y + c = 0 then the value of c is

In the pair of linear equations a_(1)x+b_(1)y+c_(1)=0" and "a_(2)y+b_(2)y+c_(2)=0" if "a_(1)/a_(2) ne b_(1)/b_(2) then the