(sin(a+b log x))/(x)

(sin x)^(log x)

int cos(log x)dx is equal to (A)(x)/(2)(cos(log x)-sin(log x))+c(B)x(cos(log x)+sin(log x))+c(C)(x)/(2)(cos(log x)+sin(log x)+c(D)x(cos(log x)-sin(log x))+c

If int(k)/(sin(x-a)sin(x-b))dx=log[(sin(x-a))/(sin(x-b))]+c, then k=

If int (1)/(sin (x -a ) cos (x -b)) dx = A log | (sin (x -a))/( cos (x -b ))| + B. Then

If int(k)/(sin(x-a)cos(x-b))dx=log[(sin(x-a))/(cos(x-b))]+c , then k=

Find the derivative of the w.r.t.x log [(sin (log x ) + x log x log (log x)]

lim_(x to 0) (A "sin" x + B log (1 + x^(2)) + C (1 - cos x))/(x^(2)) = 2 then Statement-1 : A = 1 Statement-2 : 2B + C = 4 Statement-3 A + B + C = 0

lim_(x to 0) (A "sin" x + B log (1 + x^(2)) + C (1 - cos x))/(x^(2)) = 2 then Statement-1 : A = 1 Statement-2 : 2B + C = 4 Statement-3 A + B + C = 0

int (cos x)/( sin x log sin x)dx=

The value of underset( x rarr 0 ) ( "Lim") ( sin ( ln ( 1+ x)))/( ln ( 1+ sin x )) is