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[" Q.28.A galvanic cell consists of a me...

[" Q.28.A galvanic cell consists of a metallic zinc plate immersed in "0.1MZn(NO_(3))_(2)],[" Solution and metallic plate lead in "0.02MPb(NO_(3))_(2)" solution.Write the chemical equation "],[" for the each electrode reaction,represent the cell and calculate EMF of the cell."(E_(2n)^(0)2^(2+)/2n=],[-0.76V;E_(Pb)^(0)/Pb=-0.13V)]

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A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn (NO_(3))_(2) solution and metallic plate of lead in 0.02M Pb(NO_(3))_(2) solution. Calculate the emf of the cell. Write the chemical equation for the electrode reactions and represent the cell. ("Given" : E^(@) Zn^(2+)ZN=0.76V, " " E^(@)Pb^(2+)//Pb = -0.13V)

A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn (NO_(3))_(2) solution and metallic plate of lead in 0.02M Pb(NO_(3))_(2) solution. Calculate the emf of the cell. Write the chemical equation for the electrode reactions and represent the cell. ("Given" : E^(@) Zn//Zn^(2+)=0.76V, " " E^(@)Pb^(2+)//Pb = -0.13V)

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A galvanic cell is made by dipping a Zn - rod in 0.1 (M) Zn(NO_(3))_(2) and a Pb - rod in 0.25 (M) Pb(NO_(3))_(2) solution. Calculate EMF of the cell, write the cell reaction and represent the cell. Given : E_(Pb^(2+)|Pb)^(@)=-0.13V, E_(Zn^(2+)|Zn)^(@)=-0.77V.