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x=sqrt(sin2t),y=sqrt(cos2t)...

x=sqrt(sin2t),y=sqrt(cos2t)

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x=sqrt(sin 2t),y=sqrt(cos 2 t)

x=sqrt(sin 2t),y=sqrt(cos 2 t) find dy/dx

If x=sqrt(a^(sin-1)t),y=sqrt(a^(cos-1)t) then show that (dy)/(dx)=-(y)/(x)

x = (sin^3t)/(sqrt(cos 2t)), y = (cos^3 t)/(sqrt(cos 2t)) .

Find (dy)/(dx) , if x=(sin^3t)/(sqrt(cos2t)) , y=(cos^3t)/(sqrt(cos2t))

If x=(sin^(3)t)/(sqrt(cos2t)) and y=(cos^(3)t)/(sqrt(cos2t)) , then find (dy)/(dx) .

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=(sin^3t)/(sqrt(cos2t)), y=(cos^3t)/(sqrt(cos2t))

If x=(sin^(3)t)/(sqrt(cos2t)),y=(cos^(3)t)/(sqrt(cos2t)) show that (dy)/(dx)=0att=(pi)/(6)

If x=(sin^(3)t)/(sqrt(cos 2t)) and y=(cos^(3)t)/( sqrt(cos 2t)) , show that (dy)/(dx)=0 at t=(pi)/(6) .