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[" Q 57.For the reversible reaction in e...

[" Q 57.For the reversible reaction in equilibrium "],[qquad N_(2)(g)+O_(2)(g)(k_(1))/(k_(2))2NO(g)C_(0)=Ce^(-2.1times10^(-3)t)" for the forward reaction and "],[qquad [" (a) "0=C'e^(-4.2times10^(-4))" for the backward reaction,hence "K_(c)" for the above equilibrium is "],[" (a) "5.0," (b) "2.0," (c) "0.5," (d) "2]]

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