[" उत्पाद NX निम्न द्दिये गये अभिक्रिया पदों के द्वारा बनता है "],[qquad [(M)/(3MX_(2)+X_(2))rarr M_(3)X_(8)],[M_(3)X_(8)+N_(2)CO_(3)-NX+CO_(2)+M_(3)O_(+)]],[" (दिया गाया धा।त का भार "M=56,N=23,X=80" )- "]

NX is produced by the following step of reactions M + X_(2) rightarrow MX_(2) 3MX_(2) + X_(2) rightarrow M_(3)X_(8) M_(3)X_(8) + N_(2)CO_(3) rightarrow NX + CO_(2) + M_(3)O_(4) How much M (metal) is consumed to produce 206 gm of NX? (Take at. wt of M = 56, N=23, X = 80]

If (x^(3) + 3xy^(2))/(3x^(2)y + y^(3)) = (m^(3) + 3mn^(2))/(3m^(2)n + n^(3)) , show that : nx = my .

Prove that 1-^(n)C_(1)(1+x)/(1+nx)+^(n)C_(2)(1+2x)/((1+nx)^(2))-^(n)C_(3)(1+3x)/((1+nx)^(3))+

lim_ (x rarr0) [(1-cos mx) / (1-cos nx)] = (m ^ (2)) / (n ^ (2))

lim_(x rarr 0)(sin\ x/m+cos\ (3x)/m)^((2m)//x) is

lim_(x rarr 0)(sin\ x/m+cos\ (3x)/m)^((2m)//x) is

lim_(x rarr 0)(sin\ x/m+cos\ (3x)/m)^((2m)//x) is

lim_ (x rarr0) (cos (m + 2) x-cos mx) / (cos (m + 4) x-cos (m + 2) x)

lim_(x rarr0)(cos(mx))^((n)/(x^(2))) is : (where m,n in N)

lim_(x rarr0)(1-sqrt(cos2x)*root(3)(cos3x)...root(n)(cos nx))/(x^(2))