Ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be then. Find their present ages.

Form the pair of linear equations in the following problems and find their solution by substitution method : Ten years ago, father was twelve times as old as his son and ten years hence he will be twice as old as his son will be. Find their present ages.

Ten years ago,a father was twelve xx as old as his son and ten years hence,he will be twice as old as his son will be then.Find their present ages.

Ten years ago sudhir was twelve times as old as his son Raghav and ten years hence , he will be twice as old as his son will be find their present ages .

A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages.

A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages.

Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.

Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.